\(\frac{2-x}{2001}+1=\left(\frac{1-x}{2002}+1\right)+\left(\frac{-x}{2003}+1\right)\)
\(\Leftrightarrow\frac{2003-x}{2001}=\frac{2003-x}{2002}+\frac{2003-x}{2003}\Leftrightarrow\left(2003-x\right)\left(\frac{1}{2001}+\frac{1}{2002}+\frac{1}{2003}\right)=0\)<=> x = 2003
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