a. (2x-3)2 = 36
(2x-3)2 = 62
=> TH1: 2x - 3 = 6
2x = 9
x = 9/2
TH2: 2x - 3 = -6
2x = -6 + 3
2x = -3
x = -3/2
Vậy x \(\in\){ -3/2 ; 9/2)
Câu b tương tự
a.(2x-3)^2=36
\(\Rightarrow\left(2x-3\right)^2=6^2\)
\(\Rightarrow2x-3=6\)
\(\Rightarrow2x=9\)\(\Rightarrow x=9:2=\frac{9}{2}\)
a)\(\left(2x-3\right)^2=36\)
\(\Rightarrow\left(2x-3\right)^2=6^2\)
\(\Rightarrow\hept{\begin{cases}2x-3=6\\2x-3=-6\end{cases}\Leftrightarrow\hept{\begin{cases}x=\frac{9}{2}\\x=-\frac{3}{2}\end{cases}}}\)
b)
mình xin lỗi vì nhầm 1 câu .còn 1 câu nữa là(2x-1)^3
Thiếu 1 TH nhaaaaa :
(2x-3)^2=36
\(\Rightarrow\left(2x-3\right)^2=\left(-6\right)^2\)
\(\Rightarrow2x-3=-6\Rightarrow2x=-3\Rightarrow x=\frac{-3}{2}\)
\(\left(2x-3\right)^2=36\)
=>\(\orbr{\begin{cases}2x-3=6\\2x-3=-6\end{cases}}\)
=>2x=9 hay 2x=-3
=>x=9/3 hay x=-3/2
....