(2x+1)+(3-x)=0
=>2x+1=-3+x
=>2x+1-x=-3
=>x+1=-3
=>x=-3-1=-4
Vậy x=-4
a)(2x+1)+(3-x)=0
2x+1+3-x=0
x+4=0
x=-4
vậy x=-4
(2x+1)+(3-x)=0
=>2x+1=-3+x
=>2x+1-x=-3
=>x+1=-3
=>x=-3-1=-4
Vậy x=-4
a)(2x+1)+(3-x)=0
2x+1+3-x=0
x+4=0
x=-4
vậy x=-4
(3x+2)*(x+4)-(3x-1)*(x-5)=0
help me
tìm x biêt :
a)[ 2x ] = -1
b) [x+0.4]=3
c)[2/3.x-5]=3
Tìm x,biêt
a)x+7/x+3=2x+5/2x+1
b)x-2/x-1=x+4/x+7
Giai nhanh giug mình nha
TÌM x biêt'
a) 1,35/0,2 = 1,25/0,1x
b) 2x - 3 = x + 1/2
c) ( 3x - 1/4 ) . ( x + 1/2 ) = 0
TÌM x . biêt ,
a, ( x - 1 )2 . ( x + 3 ) . ( x - 2 ) < 0
b , ( \(\frac{3}{2}\) + x ) . ( x - 1 ) > 0
Help me!!!
Tìm x biêt:
a)5x(x-1\3)=0
b)(x+1\4)(x-2\3)=0
c)1+3x=-5
d)1,5x-\(2\frac{1}{3}\)=1,5-2\3
e)2\3+1\3:x=3\5
y)\(\left(\frac{2x}{3}-3\right):\left(-10\right)=\frac{2}{5}\)
Tìm x biêt' :
a) 1/2 + 2/3 . x = 4/5
b) | x + 3/4 | - 1/2 = 0
c) ( x + 1/3 )^3 = ( -1/8 )
TÌM x biêt:
x/1=3/x+2
Tìm x biêt:|x|+|x+1|+|x+2|+|x+3|+|x+4|=6x