Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
tim x biet \(3\sqrt{x^3+8}=2x^2-6x+4\)
tim x biet (3-căn 2x)*(2-3 căn 2x)=6x-5
1, \(\sqrt{x-1}+\sqrt{x-4}=5\)
2, \(2x-7\sqrt{x}+5=0\)
3, \(\sqrt{2x+1}+\sqrt{x-3}=2\sqrt{x}\)
4, \(x-4\sqrt{x}+2021\sqrt{x-4}+4=0\)
5, \(\sqrt{2x-3}-\sqrt{x+1}=7\left(4-x\right)\)
tim a=2x+3y+z biet (x-1)^2+(y-3)^4-z^6=0
tim X nguyen duong X=\(\sqrt[3]{7+5\sqrt{2x}}+\sqrt[3]{7-5\sqrt{2x}}-1\)
Tìm x ≥ 0, biết:
a) 2x-7\(\sqrt{x}\)+3=0
b) 3\(\sqrt{x}\)+5 < 6
c) x-3\(\sqrt{x}\) -10 < 0
d) x- 5\(\sqrt{x}\) +6 = 0
e) x+ 5\(\sqrt{x}\) -14 < 0
tim x,y,z biet : x+y+z+4=2\(\sqrt{x-2}\)+4\(\sqrt{y-3}\)+6\(\sqrt{z-5}\)
giải phương trình
a) \(\left(x+\frac{5-x}{\sqrt{x}+1}\right)^2+\frac{16\sqrt{x}\left(5-x\right)}{\sqrt{x}+1}-16\)\(=0\)
b) \(\sqrt{2x-\frac{3}{x}}+\sqrt{\frac{6}{x}-2x}=1+\frac{3}{2x}\)
c) \(\sqrt{2x+1}+\frac{2x-1}{x+3}-\left(2x-1\right)\sqrt{x^2+4}-\sqrt{2}=0\)
d) \(\sqrt{x+2+3\sqrt{2x-5}}+\sqrt{x-2-\sqrt{2x-5}}=2\sqrt{2}\)
Giải phương trình
a) \(\sqrt{2x-5}=\sqrt{x+3}\)
b) \(\sqrt{2x^2-x+4}-2=x\)
c) \(\sqrt{1-x}=\sqrt{3x+2}\)
d) \(\sqrt{2x-3}=\sqrt{x-2}\)
e) \(\sqrt{x-2}-\sqrt{3+2x}=0\)
