Ta có : 3x - 7/3 - 2x - 1/2 = 7 .
=> x ( 3 - 2 ) - ( 7/3 + 1/2 ) = 7 .
=> x - ( 14/6 + 3/6 ) = 7 .
=> x - 17/6 = 7 .
=> x = 7 + 17/6 .
=> x = 59/6 .
vậy x = 59/6 .
\(3x-\frac{7}{3}-2x-\frac{1}{2}=7\)
\(\Leftrightarrow\left(3x-2x\right)-\left(\frac{7}{3}+\frac{1}{2}\right)=7\)
\(\Leftrightarrow x-\frac{17}{6}=7\)
\(\Leftrightarrow x=7+\frac{17}{6}\)
\(\Leftrightarrow x=\frac{59}{6}\)
\(\frac{3x-7}{3}\) - \(\frac{2x-1}{2}\) \(=\) \(7\)
\(\frac{3x-7}{3}\) = \(7\) + \(\frac{2x-1}{2}\)
\(\frac{3x-7}{3}\) = \(\frac{14}{2}\) + \(\frac{2x-1}{2}\)
\(\frac{3x-7}{3}\) = \(\frac{2x+13}{2}\)
<=> \(\left(3x-7\right)\) x \(2\) = \(\left(2x+13\right)\)x \(3\)
<=> \(6x-14=6x+39\) <=> 6x - 6x = 14 + 39
<=> 0x = 53 => x ko tốn tại
vậy x ko tồn tại
\(3x-\frac{7}{3}-2x-\frac{1}{2}=7\)
\(\left(3x-2x\right)-\left(\frac{7}{3}-\frac{1}{2}\right)=7\)
\(3x-2x-\frac{7}{3}+\frac{1}{2}=7\)
\(x-\frac{17}{6}=7\)
\(x=7+\frac{17}{6}\)
\(x=\frac{59}{6}\)
Vậy \(x=\frac{59}{6}\)
\(3x-\frac{7}{3}-2x-\frac{1}{2}=7\)
\(\Rightarrow\left(3x-2x\right)-\left(\frac{7}{3}+\frac{1}{2}\right)=7\)
\(\Rightarrow x-\left(\frac{14}{6}+\frac{3}{6}\right)=7\)
\(\Rightarrow x-\frac{17}{6}=7\)
\(\Rightarrow x=7+\frac{17}{6}\)
\(\Rightarrow x=\frac{42}{6}+\frac{17}{6}\)
\(\Rightarrow x=\frac{59}{6}\)
Vậy x = \(\frac{59}{6}\)
