`(3x-4)^3=7+1^2019`
`(3x-4)^3=7+1`
`(3x-4)^3=8`
`(3x-4)^3=2^3`
`=>3x-4=2`
`3x=6`
`x=2`
\(\left(3x-4\right)^3=7+1^{2019}\)
\(\left(3x-4\right)^3=7+1=8=2^3\)
\(=>3x-4=2\)
\(3x=2+4\)
\(3x=6\)
\(x=6:3\)
\(x=2\)
( 3x - 4)3 = 7 + 1
( 3x - 4)3 = 8
(3x - 4)3 = 23
3x - 4 = 2
3x = 2 + 4
3x = 6
x = 6 : 3
x = 2