\(2x^2-x=0\)
\(x\left(2x-1\right)=0\)
\(TH1:x=0\)
\(TH2:2x-1=0\)
\(2x=1\)
\(x=\dfrac{1}{2}\)
Vậy \(x\in\left\{0;\dfrac{1}{2}\right\}\)
x(2x - 1 ) = 0
=> x =0 hoặc = 0,5
5A. Tìm x, biết:
a) 8x(x - 2017) - 2x + 4034 = 0; b)
x + x2
2 8
= 0;
c) 4 - x = 2( x -4)2; d) (x2 + 1)(x - 2) + 2x = 4.
5B. Tìm x, biết:
a) x4 -16x2 =0; c) x8 + 36x4 =0;
b) (x - 5)3 - x + 5 = 0; d) 5(x - 2 ) - x2 + 4 = 0.
Tìm x biết: ( 2 x + 2 ) ( x - 1 ) – ( x + 2 ) . ( 2 x + 1 ) = 0
A. - 4 5
B. - 1 5
C. 4 5
D. 1 5
Tìm x biết: (x + 2)^2 - (x + 2)(x - 3) = 0
Tìm x biết :
a,(x+2)^2-(x+2)(x-3)=0
b,2x^3-4x^2+2x=0
c,(x-1)^2-(2x+1)^2=0
Tìm x biết:
\(\dfrac{2x+1}{x^2-2x+1}-\dfrac{2x+3}{x^2-1}=0\)
tìm x biết
a, x(2x-7)-4x+14=0
b, x(x-1)+2x-2=0
c, 2x^3+3x^2+2x+3=0
d, x^3+6x^2+11x+6=0
Bài 2: Tìm x, biết: a) (x + 2)^2 – 2(x + 2)(x – 5) = 0. b) 2x^2 + 3x – 5 = 0. c) x + 2 ^2 x 2 + 2x^3 = 0. d) (3x-1)^2-4(x+5)^2=0
Tìm x biết 2(x+3)-x^2-3x=0
x^3+27+(x+3)(x-9)=0
4x^2-25-(2x-5)(2x+7)=0
8x^3-50x=0
(2x-1)^2-25=0
Tìm x biết : a) (x+2)(x²-2x+4)-x(x²-2)=15 b) (x-4)² - (x-2)(x+2)= 6 c) x⁴-2x³+x²-2x=0
Tìm x, biết:
a) 3x(x - 1) + x - 1 = 0;
b) (x - 2)( x 2 + 2x + 7) + 2( x 2 - 4) - 5(x - 2) = 0;
c) ( 2 x - 1 ) 2 - 25 = 0;
d) x 3 + 27 + (x + 3)(x - 9) = 0.
Tìm x biết: (x-3)^2-16=0
x^2 -2x=24
(2x+1)+(x+3)^2(x+7)(x-7)=0
