\(2x^2+13x=34\)
\(\Leftrightarrow2x^2+13x-34=0\)
\(\Leftrightarrow2x^2-4x+17x-34=0\)
\(\Leftrightarrow2x\left(x-2\right)+17\left(x-2\right)=0\)
\(\Leftrightarrow\left(2x+17\right)\left(x-2\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x+17=0\\x-2\end{cases}\Rightarrow\orbr{\begin{cases}x=-\frac{17}{2}\\x=2\end{cases}}}\)
Vậy \(x=-\frac{17}{2}\) hoặc \(x=2\)