tim x biet (2x-3)^2-4.(x+1)^2=5
Tim xthuoc Z biet:
1,|2x-5|-|2x+9|=0
2,|x+1|-|x+2|-|3-x|=7
3,|2x+3|+|3x+2|-|4-x|=10
tim x , biet :
1 ) 2017 - \ x - 2017 \ = x
2) -1/2 . ( 3x - 1 ) + 3/4 . ( 3-2x) = -3 . ( x/2 - 1 ) - ( 4/5) mu -1
1)tim x biet rang:
a)3^x-1=1/243
b)2^x+2^x+3=144
c)81^-2x.27x=9^5
2)tim tiep so ghang thu 5 cua day so sau:-1/a^2;2/a^3;-6/a^4;24/a^5;...
3)tim so tu nhien x biet :
a)4^x+4^x+3=4160
b)2^x-1+5.2^x-2=7/32
Tim x biet 2(|x-1|+x-4/5)=2x-2/5
|(x+1/2).|2x-3/4||=2x-3/4 tim x biet
tim x biet |2x+3|-2|4-x|=5
Tim x biet
(x+1/5)-4=-2
(2x+3)*(x-7)=0
31/9(x)-5/2=8/3
tim x biet :
( 2-x ) x (4/5-x ) < 0
(x - 3/2) x ( 2x + 1 ) > 0
