\(\left(\frac{1}{2}-\frac{1}{3}\right).6x+6x+2=67+64\)
\(\frac{\Rightarrow1}{6}.6x+6x+2=131\)
\(\Rightarrow x+6x=131-2\)
\(\Rightarrow7x=129\)
\(\Rightarrow x=\frac{129}{7}\)
tìm x
5)
4x x 5 x 4x 3 5
6)
2
2
x 2 x 1 6
7)
2
3
(3 2) 3 .
4
x x x
8) (3x + 1). (2x- 3) – 6x.(x + 2) = 16
cho đa thức A(x)= 2(5x^3-6x^2-4x)-(10x^3-14x^2-6x+1).Tìm x, biết A(x)= -1
: Tìm x, biết:
a) 3x( 4x- 1) - 2x(6x- 3 )=30 b) 2x(3-2x) + 2x(2x-1)=15
c) (5x-2)(4x-1) + (10x +3)(2x - 1)=1 d) (x+2) (x+2)- (x -3)(x+1) = 9
e) (4x+1)(6x-3) = 7 + (3x – 2)(8x + 9) g) (10x+2)(4x- 1)- (8x -3)(5x+2) =14
Tìm x biết: 0.2:1/1/5=2/3:(6x+7)
tìm x biết x^2 -7/6x+1/3=0
(2^3)*/6x+1=64
Cho A(x)= 2(5x^2-6x^2-4x)-(10x^3-14x^2-16+1)Tìm x biết A(x)=-1
Cho A(x)= 2(5x^2-6x^2-4x)-(10x^3-14x^2-16+1)Tìm x biết A(x)=-1
Cho A(x)= 2(5x^2-6x^2-4x)-(10x^3-14x^2-16+1)Tìm x biết A(x)=-1