tim x biet x(x-1)=0
(x-1).(x+2)=0
tim x,biet
a,-x.[ x+3 ]=0
b, [ x-2 ]. [ 3x-9 ]=0
tim x biet: |x-9|+x-9=0
tim x biet(x+1)+(x+2)+...+(x+2017)=0
tim x biet (x+1)+(x+2)+.........+(x+2017)=0
tim x biet (x+1)+(x+2)+.....+(x+2013)=0
tim x biet : x^3-16x=0
Tim so nguyen x biet : |x|+|x-3|=0
tim so nguyen x biet
(x + 3)(x - 1)<0
(x - 4)(x + 3)>0