Question

Tìm x: 

a)\(\dfrac{-4}{15}:x-\dfrac{2}{7}=-\dfrac{2}{5}+\left(\dfrac{-2}{7}\right)\)

b)\(\dfrac{-5}{9}x+\dfrac{-4}{9}x-x=\dfrac{2}{3}-\dfrac{7}{6}\)

Answer 1

a)=\(\dfrac{-4}{15}:x-\dfrac{2}{7}=\dfrac{-24}{35}\)              

\(\dfrac{-4}{15}:x=\dfrac{-24}{35}+\dfrac{2}{7}\)

\(\dfrac{-4}{15}:x=\dfrac{-2}{5}\)

x=\(\dfrac{2}{3}\)

b)=x.(\(\dfrac{-5}{9}+\dfrac{-4}{9}-1\))=\(\dfrac{-1}{2}\)

x.(-2)=\(\dfrac{-1}{2}\)

x=\(\dfrac{1}{4}\)

Answer 2

\(\dfrac{-4}{15}:x-\dfrac{2}{7}=-\dfrac{2}{5}+\left(-\dfrac{2}{7}\right)\)

\(\dfrac{-4}{15}:x-\dfrac{2}{7}=-\dfrac{24}{35}\)

\(\dfrac{-4}{15}:x=-\dfrac{24}{35}+\dfrac{2}{7}\)

\(\dfrac{-4}{15}:x=-\dfrac{2}{5}\)

\(x=-\dfrac{4}{15}:\left(-\dfrac{2}{5}\right)\)

\(x=-\dfrac{4}{15}\times\dfrac{-5}{2}\)

\(x=\dfrac{2}{3}\)

 

\(\dfrac{-5}{9}x+\dfrac{-4}{9}x-x=\dfrac{2}{3}-\dfrac{7}{6}\)

\(\dfrac{-5}{9}x+\dfrac{-4}{9}x-x=-\dfrac{1}{2}\)

\(x\times\left(\dfrac{-5}{9}+\dfrac{-4}{9}-1\right)=-\dfrac{1}{2}\)

\(x\times\left(-2\right)=-\dfrac{1}{2}\)

\(x=-\dfrac{1}{2}:\left(-2\right)\)

\(x=\dfrac{1}{4}\)