a) (2x - 3)2 = 16
=> (2x - 3)2 = 42
=> \(\orbr{\begin{cases}2x-3=4\\2x-3=-4\end{cases}}\)
=> \(\orbr{\begin{cases}2x=7\\2x=-1\end{cases}}\)
=> \(\orbr{\begin{cases}x=\frac{7}{2}\\x=-\frac{1}{2}\end{cases}}\)
Vậy ...
b) 2.3x + 2 + 4. 3x + 1 = 10.36
=> 2.3x + 1. 3 + 4.3x + 1 = 10 . 36
=> 6.3x + 1 + 4.3x + 1 = 10.36
=> (6 + 4).3x + 1= 10.36
=> 10.3x + 1= 10.36
=> 3x + 1= 36
=> x + 1 = 6
=> x = 6 - 1
=> x = 5
\(a,\left(2x-3\right)^2=16\)
\(\Rightarrow\left(2x-3\right)^2=4^2\)
\(\Rightarrow2x-3=4\)
\(2x=4+3\)
\(2x=7\)
\(x=7:2\)
\(x=\frac{7}{2}\)
Tìm x
a.(2x - 3)2 =16
=> 2x - 3 = \(\pm4\)
2x-3 = 4 2x - 3 = -4
=> x = \(\frac{3}{2}\) => x = \(-\frac{1}{2}\)
a. (2x - 3)2 = 16
<=> \(\orbr{\begin{cases}\left(2x-3\right)^2=4^2\\\left(2x-3\right)^2=\left(-4\right)^2\end{cases}}\)
<=> \(\orbr{\begin{cases}2x-3=4\\2x-3=-4\end{cases}}\)
<=> \(\orbr{\begin{cases}x=\frac{7}{2}\\x=-\frac{1}{2}\end{cases}}\)
b. 2.3x+2 + 4.3x+1 = 10.36
<=> 2.3x.32 + 4.3x.3 = 10.36
<=> 3x(2.32 + 4.3) = 10.36
<=> 3x.30 = 10.36
<=> 3x+1.10 = 10.36
<=> 3x+1 = 36
<=> x + 1 = 6
<=> x = 5
a)\(\left(2x-3\right)^2=16=4^2=\left(-4\right)^2\)
\(=>\orbr{\begin{cases}2x-3=4\\2x-3=-4\end{cases}=>\orbr{\begin{cases}x=\frac{7}{2}\\x=-\frac{1}{2}\end{cases}}}\)
mk nhầm nha
2x - 3 = 4
=> x = \(\frac{7}{2}\)
sorry bạn
\(a,\left(2x-3\right)^2=16\)
\(\Rightarrow2x-3=4\)
\(\Rightarrow2x=7\)
\(\Rightarrow x=\frac{7}{2}\)
\(b,2.3^{x+2}+4.3^{x+1}=10.3^6\)
\(\Rightarrow2\left(3^{x+2}+2.3^{x+1}\right)=7290\)
\(\Rightarrow3^{x+2}+2.3^{x+1}=3645\)
\(\Rightarrow3^{x+1}\left(3+2\right)=3645\)
\(\Rightarrow3^{x+1}.5=3645\)
\(\Rightarrow3^{x+1}=729\)
\(\Rightarrow3^{x+1}=3^6\)
\(\Rightarrow x+1=6\)
\(\Rightarrow x=5\)
a)\(\left(2x-3\right)^2\)=\(16\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}2x-3=4\\2x-3=-4\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=7\\2x=-1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{7}{2}\\x=\frac{-1}{2}\end{cases}}\)
Vậy \(x\in\)\(\hept{\begin{cases}7\\2\end{cases}};\frac{-1}{2}\)