Question

Tìm x ạ

Answer 1

ĐKXĐ: \(\left\{{}\begin{matrix}x\ge0\\\sqrt{x}-2\ne0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\ge0\\x\ne4\end{matrix}\right.\)

\(\dfrac{3\left(\sqrt{x}-1\right)}{\sqrt{x}-2}=-2\\ \Leftrightarrow-2\left(\sqrt{x}-2\right)=3\left(\sqrt{x}-1\right)\\ \Leftrightarrow-2\sqrt{x}+4=3\sqrt{x}-3\\ \Leftrightarrow5\sqrt{x}=7\\ \Leftrightarrow\sqrt{x}=\dfrac{7}{5}\\ \Leftrightarrow x=\dfrac{49}{25}\left(tm\right)\)

Vậy \(x=\dfrac{49}{25}\)