Question

Tìm x 

a, 5x-15x\(^2\)=0

b, x\(^2\)+9=6x

Answer 1

\(a,\Leftrightarrow5x\left(1-3x\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{3}\end{matrix}\right.\\ b,\Leftrightarrow x^2-6x+9=0\\ \Leftrightarrow\left(x-3\right)^2=0\\ \Leftrightarrow x=3\)

Answer 2

a)\(5x-15x^2=0\\ \Rightarrow5x\left(1-3x\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{3}\end{matrix}\right.\)

b) \(x^2+9=6x\\ \Rightarrow\left(x-3\right)^2=0\\ \Rightarrow x=3\)