a) \(4590\div\left(x-24+14\right)=30\)
\(\Leftrightarrow\)\(x-10=4590\div30=153\)
\(\Leftrightarrow\)\(x=153+10=163\)
Vậy....
b) \(61\times\left(126\div x\right)=1281\)
\(\Leftrightarrow\)\(126\div x=1281\div61=21\)
\(\Leftrightarrow\)\(x=126\div21=6\)
Vậy....