Ta có: \(9\cdot5^{x-2}+7\cdot5^{x-1}-5^x=2375\)
\(\Leftrightarrow5^x\cdot\dfrac{9}{25}+5^x\cdot\dfrac{7}{5}-5^x\cdot1=2375\)
\(\Leftrightarrow5^x\cdot\dfrac{19}{25}=2375\)
\(\Leftrightarrow5^x=2375:\dfrac{19}{25}=2375\cdot\dfrac{25}{19}=3125\)
\(\Leftrightarrow5^x=5^5\)
hay x=5
Vậy: x=5