Question

Tìm x : 5x(x-2000) - x+ 2000 = 0

Answer 1

Ta có:

\(5x\left(x-2000\right)-x+2000=0\)

\(\Leftrightarrow5x\left(x-2000\right)-\left(x-2000\right)=0\)

\(\Leftrightarrow\left(5x-1\right)\left(x-2000\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}5x-1=0\\x-2000=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{5}\\x=2000\end{matrix}\right.\)

Vậy \(\left[{}\begin{matrix}x=\dfrac{1}{5}\\x=2000\end{matrix}\right.\)

Answer 2

= 5x(x-2000) - (x-2000) =0

(x-2000)(5x-1) =0

x -2000 = 0=> x=2000

5x-1 =0 => x = 1/5

Answer 3

Ta có: 5x(x-2000)-x+2000=0

5x(x-2000)+(x-2000)=0

(x-2000). (5x-1)=0

TH1: x-2000=0

x=2000

TH2: 5x-1= 0

x=1/5

Vậy x=2000 hoặc x=1/5