\(\left(4x-12\right)\left(13x-39\right)=0\)
\(\Rightarrow\orbr{\begin{cases}4x-12=0\\13x-39=0\end{cases}\Rightarrow}\orbr{\begin{cases}4x=12\\13x=39\end{cases}\Rightarrow}\orbr{\begin{cases}x=3\\x=3\end{cases}}\)
Vậy x = 3
\(\left(4x-12\right).\left(13x-39\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}4x-12=0\\13x-39=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=3\\x=3\end{cases}}\)
Vậy x=3
Ta có : 4x-12=0 hoặc 13x-39=0
Th1: 4x=12 Th2: 13x=39
x=3 x=3
Vậy x=3.
\(\left(4\times x-12\right)\times\left(13\times x-39\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}4x-12=0\\13x-39=0\end{cases}\Leftrightarrow\orbr{\begin{cases}4x=12\\13x=39\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=3\\x=3\end{cases}}}\)
Vậy \(x=3\)