Question

Tìm x:                    3^x+3^x+1+3^x+2=117

Answer 1

2 nha bạn

Chúc các bạn học giỏi

nha

Answer 2

\(3^x+3^{x+1}+3^{x+2}=117\)

\(\Rightarrow3^x+3^x\cdot3+3^x\cdot3^2=117\)

\(\Rightarrow3^x+3^x\cdot3+3^x\cdot9=117\)

\(\Rightarrow3^x\cdot\left(1+3+9\right)=117\)

\(\Rightarrow3^x\cdot13=117\)

\(\Rightarrow3^x=\frac{117}{13}\)

\(\Rightarrow3^x=9\)

\(\Rightarrow3^x=3^2\)

\(\Rightarrow x=2\)

Answer 3

2

ai tk mk

mk tk lại

hứa luôn

thank nhiều

yên tâm

Answer 4

\(3^x+3^{x+1}+3^{x+2}=117\)

\(3^x+3^x.3^1+3^x.3^2=117\)

\(3^x.\left(1+3^1+3^2\right)=117\)

\(3^x.13=117\)

      \(3^x=117\div13\)

      \(3^x=9\)

      \(3^x=3^2\)

\(\Rightarrow x=2\)

Answer 5

2 nha ban