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3/(x+2)(x+5)+5/(x+5)(x+10)+7/(x+10)(x+17)=x/(x+2)(x+17)
3/((x+2)(x+5))+5/((x+5)(x+10))+7/((x+10)(x+17))=x/((x+2)(x+17))
tim x biet
3/(x+2).(x+5) + 5/(x+5).(x+10) + 7/(x+10).(x+17) = x/(x+2).(x+17)
Với x thuộc tập hợp A = -2;-5;-10;-17
3/(x+2).(x+3) + 5/(x+5).(x+10) + 7/(x+10).(x+17) = x/(x+2).(x+17)
Tìm x:
3/(x+2).(x+3) + 5/(x+5).(x+10) + 7/(x+10).(x+17) = x/(x+2).(x+17)
3/(x+2)(x+5) + 5/(x+5)(x+10) + 7/(x+10)(x+17) = x/(x+2)(x+17)
3/ (x+2)(x+5) + 5 /(x+5)(x+10) + 7/ (x+10)(x+17) = x/ (x+2)(x+17
tìm x ae nhé
Tìm x, biết:
a) 3/(x+2)(x+5) + 5/(x+5)(x+10) + 7/ (x+10)(x+7) = x/(x+2)(x+17) với x thuộc {-2,-5,-10,-17}
b) 2/(x-1)(x-3 + 5/(x-3)(x-8) + 12/(x-8)(x-20) -1/x-20 =-3/4 với x thuộc {1,3,8,,20}
Tìm x,biết:
a,3 / (x+2).(x+5) + 5 / (x+5).(x+10) + 7 / (x+10) . (x+17)= x / (x+2).(x+17)
x∉{-2 ; -5 ;-10 ; -17}
b,2 / (x-1). (x-3)+5 / (x-3).(x-8)+12 / (x-8).(x-20)-1 / x-20=-3/4
x∉{1;3;8;20}
c,x-1/2009 + x-2/2008 = x-3/2007 + x-4 / 2006
