\(2x+\frac{3}{6}=7x-\frac{3}{15}\)
\(2x+\frac{1}{2}=7x-\frac{1}{5}\)
\(2x-7x=-\frac{1}{5}-\frac{1}{2}\)
\(-5x=-\frac{7}{10}\)
\(x=\frac{7}{50}\)
Đúng 0
Bình luận (0)