Ta có: ( x + 1 ) \(⋮\)30
=> x + 1 \(\in\)B ( 30 ) = { 0; 30 ; 60; 180 ; ...}
Mà 60 \(⋮\)x + 1
=> x + 1 = 30 hoặc x + 1 = 60
=> x = 29 hoặc x = 59.
Trl :
\(60⋮\left(x+1\right)\)
\(\Rightarrow x\in B\left(60\right)=\left\{0;60;120;...\right\}\)
\(\Rightarrow x=60\)
\(\left(x+1\right)⋮30\)
\(\Rightarrow x\in B\left(30\right)=\left\{0;30;60;...\right\}\)
\(\Rightarrow x=30\)
Mà \(60⋮\left(x+1\right)\Rightarrow x=59\)
\(\left(x+1\right)⋮30\Rightarrow x=29\)
Hc tốt