Question

tìm số tự nhiên x biết:

\(2^{x-1}\) -1 = 24 -\(\left[3^2-\left(2021^0-1\right)\right]\)

Answer 1

`2^(x-1) -1 = 24 - [3^2 - (2021^0 -1)]`

`=> 2^(x-1) -1 = 24 - [ 9 - (1-1)]`

`=> 2^(x-1) -1 = 24 - 9`

`=> 2^(x-1) -1 = 15`

`=> 2^(x-1) =15+1`

`=> 2^(x-1) = 16`

`=> 2^(x-1) = 2^4`

`=> x-1=4`

`=> x=4+1`

`=> x=5`