Question

tìm số tự nhiên x biết 

96-3(x+1)=42

Answer 1

\(96-3\left(x+1\right)=42\)

\(\Rightarrow3\left(x+1\right)=96-42=54\)

\(\Rightarrow x+1=54:3=18\)

\(\Rightarrow x=17\)

Answer 2

96 - 3(x - 1) = 42   

        3(x -1) = 96 - 42

        3(x - 1) = 54

        x - 1      = 54 :3

           x - 1   = 18

         x = 18 + 1

x = 19

Answer 3

\(96-3.\left(x+1\right)=42\)

\(3.\left(x+1\right)=96-42\)

\(3.\left(x+1\right)=54\)

\(x+1=54\div3\)

\(x+1=18\)

\(x=18-1\)

\(x=17\)

Answer 4

Lê Minh Quân sai đề bài