Question

Tìm số tự nhiên x, biết: 7^{x + 1} = 49⁵

Answer 1

`7^(x+1) = (7^2)^5`

`7^(x+1) = 7^10`

`x + 1 = 10`

`x= 9`

Answer 2

\(7^{x+1}=49^5\)

\(7^{x+1}=\left(7^2\right)^5\)

\(7^{x+1}=7^{10}\)

`=>x+1=10`

`x=10-1`

`x=9`

Answer 3

\(7^{x+1}=49^5\\ =>7^{x+1}=\left(7^2\right)^5\\ =>7^{x+1}=7^{10}\\ =>x+1=10\\ =>x=9\)

Answer 4

\(7^{x+1}=49^5\)

\(7^{x+1}=\left(7^2\right)^5\)

\(7^{x+1}=7^{10}\)

\(\Rightarrow x+1=10\)

    \(x=9\)

Answer 5

7^x+1= ( 7²)⁵

<=> 7^x+1=7¹⁰

<=> x + 1 = 10

<=>x = 9

Answer 6