\(\left(5x+7\right)⋮\left(3x+2\right)\)
\(3\left(5x+7\right)-5\left(3x+2\right)⋮\left(3x+2\right)\)
\(15x+21-15x-10⋮\left(3x+2\right)\)
\(11⋮\left(3x+2\right)\)
\(\left(3x+2\right)\inƯ\left(11\right)=\left\{1;11\right\}\)
Mà 3x + 2 > 0 nên 3x + 2 = 11
Vậy x = 3
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