2 + 4 + 6 + 8 + ... + 2.x = 210
=> 2.1 + 2.2 + 2.3 +2.4 + ... + 2.x = 210
=> 2.( 1 + 2 + 3 + 4 + ... +x ) = 210
=> 2. [ x.( x+ 1) /2 ] = 210
=> x. ( x + 1 ) = 210
hay x.( x + 1) = 14.(14 + 1)
Vậy x = 14
2+4+6+8+...+2x=210
+) Ta có : 2.1+2.2+2.3+2.4+...+2x=210
=>2.(1+2+3+...x) =210
1+2+3+...+x= 210:2
1+2+3+...+x= 105
(x+1).x:2=105 =>(x+1).x=210 =>15.14=210 +) Vậy x=14
2.[x.(x+1)/2]=210 có nghĩa là như thế nào
2 + 4 + 6 + 8 + ... + 2x = 210
[ ( 2x -2 ) : 2 + 1 ] . ( 2x + 2 ) : 2 = 210
[ ( 2x - 2.1) : 2 + 1 ] . ( 2x + 2.1 ): 2 = 210
[ 2 ( x -1 ) : 2 + 1 ] . 2 ( x + 1 ) : 2 = 210
[ ( x -1 ) + 1 ] . ( x + 1 ) = 210
x . ( x + 1 ) = 210
x . ( x + 1 ) = 14 . 15
=> x = 14
2=2.1
4=2.2
6=2.3
2x=2.x
do đó 2;4;6;...;2x có x số hạng
Ta có (2x+2).x:2=210
(2x+2.1).x=420
(x+1).x=210
(x+1).x=15.14
Vậy x=14
2+4+6+8+...+2x =210
= 2 (1+2+3+...+x)=210
= 2 [x (x+1)] = 210
= x (x+1) = 210
Vì 210 = 14×15 nên 14 (14+1) =210
Vậy x =14