Question

Tìm số tự nhiên n sao cho:

4n+14\(⋮\)n+1

Answer 1

\(\left(4n+14\right)⋮\left(n+1\right)\)

\(\Leftrightarrow4\left(n+1\right)+10⋮\left(n+1\right)\)

\(\Leftrightarrow\left(n+1\right)\inƯ\left(10\right)=\left\{1;-1;2;-2;5;-5;10;-10\right\}\)

Do \(n\in N\)

\(\Leftrightarrow n\in\left\{0;1;4;9\right\}\)