đặt \(A=\frac{2n+6}{n+1}=\frac{2n+2+4}{n+1}=\frac{2\left(n+1\right)}{n+1}+\frac{4}{n+1}\)
Để A tối giản thì \(2n+6⋮n+1\)mà \(\frac{2\left(n+1\right)}{n+1}⋮n+1\)nên \(4⋮n+1\)
\(4⋮n+1\Rightarrow n+1\inƯ\left(4\right)=\left\{\pm1;\pm2;\pm4\right\}\)
\(\Rightarrow n\in\left\{0;-2;1;-3;3;-5\right\}\)
Vì \(n\in N\Rightarrow n\in\left\{0;1;3\right\}\)