Question

Tìm số tự nhiên n, để n+4 chia hết cho n+1

Answer 1

ta có:

\(n+4⋮n+1\)

\(\Rightarrow n+1+3⋮n+1\)

\(\Rightarrow3⋮n+1\)

\(\Rightarrow n+1\inƯ\left(3\right)\)

\(Ư\left(3\right)=\left\{\pm1;\pm3\right\}\)

n+1	-3	-1	1	3
n	-4	-2	0	2

Vậy ................................. kb nha

Answer 2

n + 4 \(⋮\)n + 1 \(\Rightarrow\)n + 1 + 4 \(⋮\)n + 1 

\(\Rightarrow\)4 \(⋮\)n + 1 

\(\Rightarrow\)n + 1 \(\in\)Ư(4) = { 1;2;4}

\(\Rightarrow\)n \(\in\){ 0;1;3}

Vậy n \(\in\){ 0;1;3}