\(x< \frac{1}{3}+\frac{15}{9}\)
=> \(x< \frac{3}{9}+\frac{15}{9}\)
=> \(x< \frac{18}{9}\)
=> \(x< 2\)
mà x là số tự nhiên nên x = 0 hoặc x = 1
\(x< \frac{1}{3}+\frac{15}{9}\)
\(x< \frac{3}{9}+\frac{15}{9}\)
\(x< \frac{18}{9}\)
\(x< 2\)
Vì \(x\in N\Rightarrow x\in\left\{0;1\right\}\)
Vậy \(x\in\left\{0;1\right\}\)