Question

Tìm số nguyên x,biết

(3-x)+(x-5)=29-x

15+x-(3+x)=x-14

Answer 1

\(\left(3-x\right)+\left(x-5\right)=29-x\)

\(3-x+x-5+x=29\)

\(x-2=29\)

\(x=31\)

vậy \(x=31\)

\(15+x-\left(3+x\right)=x-14\)

\(15+x-3-x-x=-14\)

\(-x+12=-14\)

\(-x=-26\)

\(x=26\)

vậy \(x=26\)

Answer 2

a, => 3-x+x-5 = 29-x

=> -2 = 29-x

=> x=29-(-2) = 31

b, => 15+x-3-x=x-14

=> 12=x-14

=> x=12+14=26

Tk mk nha

Answer 3

1, 

     (3-x)+(x-5) =29-x

=> (x-x) + (3-5) = 29 - x

=>            -2     = 29 -x

=>            -31  = -x

Vậy x=31

2,

    15+x-(3+x)=x-14

=> (x-x) + (15-3) = x-14

=>            12       = x-14

=>            12+14 =x

Vậy x= 26