\(2x+12=3\left(x-7\right)\)
\(\Leftrightarrow2x+12=3x-21\)
\(\Leftrightarrow12+21=3x-2x\)
\(\Leftrightarrow x=33\)
=> 2x+12 = 3x-21
=> 2x = 3x-21-12 = 3x-33
=> 33 = 3x-2x
=> x=33
Vậy x = 33
Tk mk nha
2x + 12 = 3( x - 7 )
<=> 2x + 12 = 3x - 21
<=> 12 + 21 = 3x - 2x
=> 33 = x
Vậy x = 33