\(\frac{n^2+5}{n-1}=\frac{n\left(n-1\right)+n+5}{n-1}=\frac{n\left(n-1\right)}{n-1}+\frac{n+5}{n-1}=n+\frac{n+5}{n-1}\in Z\)
\(\Rightarrow n+5⋮n-1\)
\(\Rightarrow\frac{n+5}{n-1}=\frac{n-1+6}{n-1}=\frac{n-1}{n-1}+\frac{6}{n-1}=1+\frac{6}{n-1}\in Z\)
suy ra 6 chia hết n-1....