Question

Tìm số nguyên n khi

27^n:3^n=9

25/5^n=5

Answer 1

a)\(27^n:3^n=9\)

\(\Rightarrow9^n=9\)

\(\Rightarrow n=1\)

b)\(\frac{25}{5^n}=5\)

\(\Rightarrow5^n=5\)

\(\Rightarrow n=1\)

Answer 2

a)27\(^n\)\(\div\)3\(^n\)=9

⇒9\(^n\)=9

⇒n=1

b)\(\frac{25}{5n}\) =5

⇒5\(^n\)=5

⇒n=1

Answer 3

 a)  \(27^n:3^n=9\)

\(\left(27:3\right)^n=9\Leftrightarrow9^n=9\)

\(\Rightarrow n=1\)

b) \(\frac{25}{5^n}=5\)

\(\frac{25}{5}=5^n\Leftrightarrow5=5^n\)

\(\Rightarrow n=1\)

Vậy .................................................