Question

Tìm phân số tối giản \(\dfrac{a}{b}\) biết: \(\dfrac{1}{3}\) - \(\dfrac{1}{2}\) + \(\dfrac{a}{b}\) = \(\dfrac{1}{2}\)

Answer 1

\(\dfrac{1}{3}-\dfrac{1}{2}+\dfrac{a}{b}=\dfrac{1}{2}\)

\(\Leftrightarrow\dfrac{a}{b}=\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}\)

\(\Leftrightarrow\dfrac{a}{b}=\dfrac{2}{2}-\dfrac{1}{3}\)

\(\Leftrightarrow\dfrac{a}{b}=1-\dfrac{1}{3}\)

\(\Leftrightarrow\dfrac{a}{b}=\dfrac{3}{3}-\dfrac{1}{3}\)

\(\Leftrightarrow\dfrac{a}{b}=\dfrac{2}{3}\)

Vậy phân số tối giản \(\dfrac{a}{b}=\dfrac{2}{3}\)