Question

tim nghiem da thuc 

a)2x+7

b)\(^{x^2}\)+5x+4

Answer 1

a) không biết

b) \(\Leftrightarrow x^2+x+4x+4=x\left(x+1\right)+4\left(x+1\right)=0\)

\(\Leftrightarrow\left(x+1\right)\left(x+4\right)=0\Rightarrow\orbr{\begin{cases}x=-1\\x=-4\end{cases}}\)