Ta có:
\(3^2\times3^n=3^n\)
\(\Rightarrow3^{n+2}=3^n\)
\(\Rightarrow n+2=n\)(Vô lí)
Vậy \(n\in\varnothing\)
T**k mik nhé!
\(3^2.3^n=3^n\)
\(\Leftrightarrow9.3^n=3^n\)
\(\Leftrightarrow9=3^n\div3^n\)
\(\Leftrightarrow9=1\left(voli\right)\)
\(\Rightarrow n\in\left\{\varnothing\right\}\)
\(3^2.3^n=3^n\)
\(\Leftrightarrow9.3^n=3^n\)
\(\Leftrightarrow9=3^n\div3^n\)
\(\Leftrightarrow9=1\) (vô lí )
Vậy \(x\in\left\{\varnothing\right\}\)