\(A=\sqrt{14-x}+\sqrt{x-10}\)
Đk:\(10\le x\le14\)
\(A^2=\left(\sqrt{14-x}+\sqrt{x-10}\right)^2\)
\(=\left(14-x\right)+\left(x-10\right)+2\sqrt{\left(14-x\right)\left(x-10\right)}\)
\(=4+2\sqrt{\left(14-x\right)\left(x-10\right)}\)
\(\le4+\left(14-x\right)+\left(x-10\right)\) (BĐT AM-GM)
\(=4+4=8\Rightarrow A^2\le8\Rightarrow A\le\sqrt{8}\)
tim x de : -(\(\sqrt{x}\)-1) * p = 2 * \(\sqrt{x+2}\)
biet p = -(\(\sqrt{x}\)- 1)
cac ban giai ho minh mk dang can gap
giup to nhe cac ban
tim x
4/x+can(x-1/x)=x+can(2*x-5/x)
\(\frac{x+\sqrt{xy}}{\sqrt{x}-\sqrt{y}}\)
cac ban chi cach triet tieu giup minh ik =')))
giai phuong trinh (x-1)^2016+(x-2)^2016=1
cac ban lam giup bai nay cho minh vs. minh dang can gap. thank you nhiu
cac ban giai giup mk bai nay nha
\(\sqrt{19+8\sqrt{3}}-\sqrt{19-8\sqrt{3}}=?\)
\(\sqrt{x+2\sqrt{x-1}}+\sqrt{x-2\sqrt{x-1}}=?\)
giup dum minh voi nha cac ban :
\(\sqrt{4+\sqrt{5.\sqrt{3+5.\sqrt{48-10\sqrt{7+4\sqrt{3}}}}}}\)
Giup minh voi : cho P= \(\sqrt{x-1}\)+\(\sqrt{3-x}\)Tim GTLN,GTNN cua P
Cho tam giác ABC.Về phía ngoài của tam giác ta dựng các tam giác vuông cân ABE và ACF dinh A Chung minh trung tuyen AI cua tam giac ABC thi vuong goc voi EF via AI= 1/2 EF
Mong cac ban giai giup minh, minh dang can gap.
Chung minh vo nghiem
sqrt(10-x^2)=x-4
Giai giup em bai nay voi oi nguoi. E cam on