\(M=\frac{3x^2-4x}{^{\left(x-1\right)^2}}=\frac{3\left(x^2-2x+1\right)+2\left(x-1\right)-1}{\left(x-1\right)^2}=3+\frac{2y-1}{y^2}\)
\(4-\left(\frac{1}{y^2}-\frac{2}{y}+1\right)=4-\left(\frac{1}{y}-1\right)^2\)
Mmax =4 khi y=1; x=2
\(M=\frac{3x^2-4x}{^{\left(x-1\right)^2}}=\frac{3\left(x^2-2x+1\right)+2\left(x-1\right)-1}{\left(x-1\right)^2}=3+\frac{2y-1}{y^2}\)
\(4-\left(\frac{1}{y^2}-\frac{2}{y}+1\right)=4-\left(\frac{1}{y}-1\right)^2\)
Mmax =4 khi y=1; x=2
Tim Min va Max cua bieu thuc A=(3-4x):(x^2+1)
1)Tim MAX cua A= (6x^2-2x+1)/ x^2
2)tim MIN va MAX C= (3-4x)/(X^2+1)
3) Tim MIN va MAX P = x^2+y^2
biet giua x va y co moi quan he nhu sau : 5x^2+8xy+5y^2=36
4)tim MAX Q = -x^2-y^2+xy+2x+2y
tim max va min cua D=\(\frac{3-4x}{x^2+1}\)
GIẢI NHANH NHÉ !!!
\(\frac{3-4x}{x^2+1}\)
Tim GTLN(max) cua BT
TRA LOI NHANH HO TUI NHE
tim gia tri x nguyen de bieu thuc (3x2-4x+x-1)/(3x+2) co gia tri nguyen
tim gia tri x nguyen de bieu thuc (3x3-4x2+x+1)/(x-4) co gia tri nguyen
tim max cua :
1/(x+2017)2
tim MAX va MIN cua bieu thuc sau A=(8x+15)/(x2+1)
tim max,min nếu có của biểu thức sau: M= 4x-3/x2+1
tim max cua 2xy-x2-4y2