x/2=y/5=k suy ra x=2k; y=5k
5kx2k=40
10k^2=40
k^2=40:10=4
k=-2(x;y<0)
ta có; x=-2x2=-4
y=-2x5=-10
\(\frac{x}{2}=\frac{y}{5}\Leftrightarrow\frac{x.y}{2.5}=\frac{40}{10}=4\)
\(\Rightarrow\frac{x}{2}=4\Rightarrow x=8\)
\(\Rightarrow\frac{y}{5}=4\Rightarrow y=20\)
\(\frac{x}{2}=\frac{y}{5}=>=\frac{x}{2.k}=\frac{y.}{5.k}\left(k\right)khác0\)
mà x.y=40
=>2k.5k=40
=>(2.5)k=40
10k=40
k=40:10
k=4
=>\(\frac{x}{2k}=\frac{x}{5k}=\frac{x}{2.4}=\frac{y}{5.4}=\frac{x}{8}=\frac{y}{20}\)
=>x.k=x.4=8
x=2
y.k=y.4=20
y=5