\(P=\sqrt{x^2+4}+\frac{1}{\sqrt{x^2+4}}=\frac{3}{4}\sqrt{x^2+4}+\frac{\sqrt{x^2+4}}{4}+\frac{1}{\sqrt{x^2+4}}\)
\(\Rightarrow P\ge\frac{3}{4}\sqrt{x^2+4}+2\sqrt{\frac{\sqrt{x^2+4}}{4\sqrt{x^2+4}}}=\frac{3}{4}\sqrt{x^2+4}+1\)
\(\Rightarrow P\ge\frac{3}{4}\sqrt{4}+1=\frac{5}{2}\)
\(\Rightarrow P_{min}=\frac{5}{2}\) khi \(x=0\)