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\(A=|x+3|+|x-9|=|x+3|+|9-x|\ge|x+3+9-x|=12.\)
Dấu "=" xảy ra \(\Leftrightarrow\left(x+3\right)\left(9-x\right)\ge0\)
\(\Leftrightarrow-3\le x\le9\)
Vậy: Amin=12\(\Leftrightarrow-3\le x\le9\)
cho bieu thucA=\(\frac{8-x}{x-3}\)
tim gia tri cua x de A co gia tri bang gia tri bieu thuc M=x+1
AE giup cai
tim gtnn cua bieu thuc |x+3|+|11-x|
tim gtnn cua bieu thuc sau (x^2 -9x)^2+ |y-2 | +10
tinh gia tri bieu thuc E = x^10 - 2014 x^9 -2014 x^8 - ... - 2014 x -1 biet x=2015
Tim GTNN cua bieu thuc
A=6/ /x/ - 3 ( x thuoc Z)
Tim GTNN cua bieu thuc A=|x-7|+6-x
tim GTNN cua bieu thuc A=x-2017|x - 2017| + |x - 2018| + |x - 2019|
tim gtnn cua bieu thuc sau
A= 3/4+|x-1/5|
Tim GTNN cua bieu thuc:
B=|x-2|+|x-6|+5
tim gtnn cua bieu thuc:
A=|x|+|8-x|