Question

tìm gtln(nếu có)

y=\(\dfrac{3sin^2x\left(1-4sin^2x\right)}{cos^4x}\)

Answer 1

\(y=\dfrac{3sin^2x-12sin^4x}{cos^4x}=3tan^2x.\dfrac{1}{cos^2x}-12tan^4x=3tan^2x\left(1+tan^2x\right)-12tan^4x\)

\(=-9tan^4x+3tan^2x=-9\left(tan^2x-\dfrac{1}{6}\right)^2+\dfrac{1}{4}\le\dfrac{1}{4}\)