Chọn C
A = lim x → 0 4 x + 1 − 1 x − lim x → 0 2 x + 1 3 − 1 x
lim x → 0 4 x + 1 − 1 x = lim x → 0 4 x x 4 x + 1 + 1 = lim x → 0 4 4 x + 1 + 1 = 2
lim x → 0 2 x + 1 3 − 1 x = lim x → 0 2 x x ( 2 x + 1 ) 2 3 + 2 x + 1 3 + 1 = 2 3
Vậy A = 2 − 2 3 = 4 3