Do hàm bậc 2 có GTNN trên R nên \(m>0\)
\(\Rightarrow\frac{4ac-b^2}{4a}=-10\)
\(\Leftrightarrow\frac{4m\left(-3m-2\right)-4m^2}{4m}=-10\)
\(\Leftrightarrow-16m-8=-40\)
\(\Rightarrow m=2\)
Xét m= 0
\(\Rightarrow y=-2\)
Xét m khác 0
\(-\frac{\Delta}{4a}=10\Leftrightarrow\frac{-\left(-2m\right)^2+4\left(-3m-2\right)m}{4m}=10\)
\(\Leftrightarrow-4m^2-12m^2-8m=40m\)
\(\Leftrightarrow16m^2+48m=0\Leftrightarrow\left[{}\begin{matrix}m=-3\\m=0\left(l\right)\end{matrix}\right.\)
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