Question

Tìm giá trị của x để biểu thức sau có số chỉ bằng 0

1/6(1-3x)-1/(3x-1)^2+1/6(3x+11)+3/(3x+11)^2

Answer 1

\(\dfrac{1}{6\left(1-3x\right)}-\dfrac{1}{\left(3x-1\right)^2}+\dfrac{1}{6\left(3x+11\right)}+\dfrac{3}{\left(3x+11\right)^2}=0\)

\(\Leftrightarrow\dfrac{-1}{6\left(3x-1\right)}-\dfrac{1}{\left(3x-1\right)^2}=\dfrac{-1}{6\left(3x+1\right)}-\dfrac{3}{\left(3x+11\right)^2}\)

\(\Leftrightarrow-\left(3x-1\right)-6=-1\left(3x+11\right)-18\)

=>-3x+1-6=-3x-11-18

=>-3x-5=-3x-19

=>-5=-19(vô lý)