\(3xy-3x-y=0\)
\(\Rightarrow3x\left(y-1\right)-\left(y-1\right)=0+1\)
\(\Rightarrow\left(3x-1\right)\left(y-1\right)=1\)
\(\Rightarrow\left(3x-1\right);\left(y-1\right)\inƯ\left(1\right)=\left\{\pm1\right\}\)
Xét bảng
3x-1 | 1 | -1 |
y-1 | 1 | -1 |
x | 2/3 | 0 |
y | 2 | 0 |
Vậy.............................