`Answer:`
Ta có:
\(-\frac{1}{3}=-\frac{12}{36}\)
\(-\frac{1}{4}=-\frac{9}{36}\)
\(\frac{y}{18}=\frac{2y}{36}\)
\(\Rightarrow-\frac{12}{36}< \frac{x}{36}< \frac{2y}{36}< -\frac{9}{36}\)
\(\Rightarrow\left(-12\right)< x< 2y< \left(-9\right)\)
\(\Rightarrow\left(-12\right)< \left(-11\right)< 2.\left(-5\right)< \left(-9\right)\)
\(\Rightarrow\left(-12\right)< \left(-11\right)< \left(-10\right)< \left(-9\right)\)
Vậy `x=(-11);y=(-9)`